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Setler79 [48]
4 years ago
9

Find the critical values

Mathematics
1 answer:
sesenic [268]4 years ago
4 0

Answer: this is very hard and i was wondering if there is more info

Step-by-step explanation:

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3 years ago
Given: LM ∥ KN<br> LP ⊥ KN , KL = MN<br> KN = 30, LM = 20<br> m∠KLM=126°<br> Find: LP
Ronch [10]

An angle is produced at the <u>point</u> where two or more lines<em> meet</em>. Thus the <u>value</u> of LP required in the question is approximately 14.

Two<em> lines</em> are said to be <em>perpendicular</em> when a <u>measure</u> of the angle <u>between</u> them is a <em>right angle</em>. While <u>parallel</u> lines are lines that do not meet even when <u>extended</u> to <em>infinity</em>.

From the question, let the <u>length</u> of LP be represented by x.

Thus, from the given question, it can be <u>deduced </u>that;

LM ≅ PN = 20

KP = KN - PN

    = 30 - 20

KP = 10

LP = x

Also,

<MLP is a right angle, so that;

< KLP = < KLM - <PLM

         = 126 - 90

<KLP = 36^{o}

So that applying the Pythagoras theorem to triangle KLP, we have;

Tan θ = \frac{opposite}{adjacent}

Tan 36 = \frac{10}{x}

x = \frac{10}{Tan 36}

  = \frac{10}{0.7265}

x = 13.765

Therefore the <em>side</em> LP ≅ 14.

For more clarifications on segments and angles, visit: brainly.com/question/4976881

#SPJ1

5 0
2 years ago
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