1 Move all terms to one side.
{x}^{2}+15x+45=0
x
2
+15x+45=0
2 Use the Quadratic Formula.
x=\frac{-15+3\sqrt{5}}{2},\frac{-15-3\sqrt{5}}{2}
x=
2
−15+3
5
,
2
−15−3
5
3 Simplify solutions.
x=-\frac{3(5-\sqrt{5})}{2},-\frac{3(5+\sqrt{5})}{2}
x=−
2
3(5−
5
)
,−
2
3(5+
5
)
The statement is True, Monte Carlo simulation generate many outcomes that are organized into a frequency distribution.
Monte Carlo simulation
- When the possibility of random variables is available, a Monte Carlo simulation is a model that is used to forecast the likelihood of a variety of events. Monte Carlo simulations assist in illuminating how risk and uncertainty affect forecasting and prediction models
- The potential accuracy of a Monte Carlo simulation is roughly 4%, which is still higher than the 1% accuracy stated by SAMPLE, even for a random function with a 3 error factor.
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The domain of g(x) is [4, 7)
<h3>How to determine the domain of g(x)?</h3>
The function is given as:
g(x) = f(x + 3)
Since f(x) is a function, then g(x) is also a function
The domain of f(x) is given as:
[1, 4)
The equivalent of these values in g(x) are
x = 1 + 3 = 4
x = 4 + 3 = 7
Hence, the domain of g(x) is [4, 7)
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Answer:
2.83
Step-by-step explanation:
d= Square root of (x2 - x1 )^2 +( y2- y1)^2
from the point given you
x1= -6
y1 = -17
x2 = -8
y2 = -19
by applying the formula
Square root of ( -8 - (-6))^2 + ( -19 - (-17))^2
Square root of (-8+6) + (-19+17)^2
Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
