Answer:
The common ratio is -2
Next three terms are 18, -36, and 72
Step-by-step explanation:
The common ratio is -2 since each consecutive term is being multiplied by -2
The next three terms are -9(-2) = 18, 18(-2) = -36, and -36(-2) = 72
4x99=396in
1 yard=36 in
so there for mandy needs 11 yards of trim
Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation,
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
![P(x\geq 10)=0.99](https://tex.z-dn.net/?f=P%28x%5Cgeq%2010%29%3D0.99)
Assume the bag weight distribution is bell-shaped
Therefore,
![P(\frac{x-\mu}{\sigma}\geq 10)=0.99](https://tex.z-dn.net/?f=P%28%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cgeq%2010%29%3D0.99)
We know that
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Using the value of z
Now,
![\frac{10-\mu}{0.2}=0.99](https://tex.z-dn.net/?f=%5Cfrac%7B10-%5Cmu%7D%7B0.2%7D%3D0.99)
![10-\mu=0.99\times 0.2](https://tex.z-dn.net/?f=10-%5Cmu%3D0.99%5Ctimes%200.2)
![\mu=10-0.99\times 0.2](https://tex.z-dn.net/?f=%5Cmu%3D10-0.99%5Ctimes%200.2)
![\mu=9.802](https://tex.z-dn.net/?f=%5Cmu%3D9.802)
Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
The total measure of all the angles in a triangle is 180°.
Since there is already a 90° angle, the other 2 angles must also add up to 90°.
The only answer that fits is x = 9.
Check:
9x7 = 63°
3x9 = 27°
Add up = 90°
:)