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marishachu [46]
3 years ago
12

4n-(7-6n) Helppp plz

Mathematics
1 answer:
belka [17]3 years ago
4 0
4n - (7-6n)
4n -7 +6n (multiply minus to 7-6n)
10n -7 is the answer
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diamong [38]
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8 0
3 years ago
Given A = {x | x < 1}, B = {x | x ≥ 5}, and C = {x | x = 5}, match the following items. 1. A B Ø 2. A C {x | x ≥ 5} 3. B C {x
ivann1987 [24]

Answer:

The matching is shown below.

Step-by-step explanation:

The given sets are defined as

A = {x | x < 1}

It means all the values of x which are less than 1.

B = {x | x ≥ 5}

It means all the values of x which are greater than or equal to 5.

C = {x | x = 5}

It means all the value of x is 5.

Union of two sets contains all the elements of both sets.

Intersection of two sets contains only common elements of both sets.

The matching is shown below.

        Sets                              Correct value

1.     A ∪ B                         {x | x < 1 or x ≥ 5}

2. A ∪ C                         {x | x < 1 or x = 5}

3. B ∪ C                         {x | x ≥ 5}

4. A ∩ B                         Ø

5. B ∩ C                         {x | x = 5}

6 0
3 years ago
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Step-by-step explanation:

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3 years ago
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What is the volume of the solid?
Evgen [1.6K]

9514 1404 393

Answer:

  (9√3 -3π/2) ft^3 ≈ 10.88 ft^3

Step-by-step explanation:

The area of the hexagon is given by the formula ...

  A = (3/2)√3·s^2 . . . . for side length s

The area of the hexagonal face of this solid is ...

  A = (3/2)√3·(2 ft)^2 = 6√3 ft^2

__

The area of the circular hole in the hexagonal face is ...

  A = πr^2

The radius is half the diameter, so is r = (2 ft)/2 = 1 ft.

  A = π(1 ft)^2 = π ft^2

Then the area of the "solid" part of the face of the figure is ...

  A = (6√3 -π) ft^2

__

The volume is ...

  V = Bh . . . . . where B is the area of the base of the prism, and h is its height

  V = ((6√3 -π) ft^2)(3/2 ft) = (9√3 -3π/2) ft^3 ≈ 10.88 ft^3

8 0
3 years ago
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