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3 years ago

HELP 50 POINTS

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer: #2

Step-by-step explanation:

Paul [167]3 years ago

7 0

Answer:

Step-by-step explanation:

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The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 14

Salsk061 [2.6K]

Question Completion

PIE CHART NUMBERS:

Excellent 9%
Good 41%
Fair 36%
Poor 13%
Other 1%

Answer:

0.000063

Step-by-step explanation:

Number of Respondents, n=1400

Probability that they would rate their financial shape as excellent = 0.09

Number of Those who would rate their financial shape as excellent

=0.09 X 1400

=126

Therefore:

The probability that 4 people chosen at random would rate their financial shape as excellent

$=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)$

6 0

3 years ago

URGENTT!!!! help quick please

omeli [17]

The answer is going to be
X=20

7 0

3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

4 years ago

An artist is creating a sculpture where a globe with a diameter of 48 inches sits in a cone like a scoop of ice cream. She wants

brilliants [131]

Answer:

115.2 inches

Step-by-step explanation:

What we must do is calculate the ratio between the real version and the version to be imitated, in this case the ice cream cone.

To calculate the ratio, we will do it through the diameter:

48 / 2.5 = 19.2

So the ratio is 19.2: 1

Which means that one inch of the ice cream cone represents 19.2 inches in the real version.

Therefore, in the case of height it would be:

6 * 19.2 = 115.2

Therefore, the height should be 115.2 inches.

8 0

3 years ago

Please help for test due today

krek1111 [17]

I don’t really know, but it could be b or c. If none then just pick a question :D

3 0

3 years ago