Let n be the amount of 80% solution; and 150-n be the amount of 20% solution. Then:
.8n+.2(150-n)=.6(150)
.8n+30-.2n=90
.6n=60
n=100
150-n=50
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= 1455
generate a few terms of the sequence using 
= 3n + 2
= ( 3 × 1) + 2 = 5
= (3 × 2) + 2 = 8
= (3 × 3 ) + 2 = 11
= (3 × 4 ) + 2 = 14
= ( 3 × 5 ) + 2 = 17
the terms are 5, 8, 11, 14, 17
these are the terms of an arithmetic sequence
sum to n terms is calculated using 
= 
[ 2a + (n-1)d]
where a is the first term and d the common difference
d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and = 5
= 
[( 2 × 5) + (29 × 3) ]
= 15( 10 + 87) = 15 × 97 = 1455
The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
According to the given question.
We have some linear equations.
xy = 4n + 3
yz = 2n - 7
and
xz = 20
Since, y is between x and z. Which means y, x and z are collinear points.
Therefore,
xy + yz = xz
⇒ 4n + 3 + 2n - 7 = 20
⇒ 6n -4 = 20
⇒ 6n = 20 + 4
⇒ 6n = 24
⇒ n = 24/6
⇒ n = 4
Therefore,
yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1
Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
Find out more information about collinear points here:
brainly.com/question/1593959
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There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:
R(90 deg) : (X,Y) ---> (-Y,X)
Using the given coordinates:
R(90 deg<span>) : (-4,1) ---> (-1,-4)
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Therefore, Point C' will be located at (-1,-4)
