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alexandr1967 [171]
3 years ago
9

Find the surface area of the isosceles triangular prism below.

Mathematics
1 answer:
Simora [160]3 years ago
3 0
The answer is 637.222 in^2

Because I am right
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90% as a decimal is .9 and then as a fraction in simplest form is 9/10
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Analyze Relationships A scale for a scale drawing is 10 cm:1mm. Which is larger, the actual object or the scale drawing: Explain
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If you're saying that the scale is 10 cm: 1 mm then the scale will be larger than the actual object because for every 1 mm of the object it will equal 10 cm of the scale drawing.
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-13 =\dfrac r9+8−13= <br> 9<br> r<br> ​ <br> +8
inna [77]

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Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.

56738w7421098548091672949123749279102

Step-by-step explanation:

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3 years ago
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Casey bought 6 bags of apples. Each bag contained 5 apples. How many
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30 apples bc 5x6 (5 six times) =30
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3 years ago
A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found
irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

H_a: p > 0.04

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0
3 years ago
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