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3 years ago

What is the solution to system of linear equations graphed here?

Mathematics

1 answer:

Ghella [55]3 years ago

5 0

Answer:

Step-by-step explanation:

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I made my own tricky math question. But I don't know if its tricky for you. Amelia has 1 notebook on her desk, she put her noteb

fomenos

Answer:

1 thing, her pouch

Step-by-step explanation:

you sayed that she took her notebook away and the only thing onher desk is her pouch

5 0

3 years ago

The expression 6x2 gives the surface area of a cube, and the expression x3 gives the volume of a cube, where x is the length of

Katena32 [7]

Answer:

Surface of a cube = S(x)

S(x)=6x²

S(2m)=6(2m)²=6(4m²)=24m²

The surface of this cube is 24m².

Volume of a cube = V(x)

V(x)=x³

V(2m)=(2m)³=8m³

The volume of this cube is 8m³ .

5 0

4 years ago

What is the area of a square window that has a perimeter of 52 feet? 13 104 169 225

Ymorist [56]

The perimeter and area of a square of side $l$ are given by the following formulas:

$p = 4l,\quad A = l^2$

Since we know the perimeter, we can invert the first equation to deduce the side length:

$52 = 4l \iff l = \frac{52}{4} = 13$

And now that we know the side length, we have to square it to get the area:

$A = l^2 = 13^2 = 169$

6 0

3 years ago

Read 2 more answers

I need help solving this problem.

lys-0071 [83]

Answer:

The one on the left has a width of 6 feet. The one on the right has a width of 5 ft.

A. The ratio would be 6/5 ( left over right)

B. Volume is cubed so the ratio of their volumes would be:

6^3 / 5^3 = 216 / 125

5 0

3 years ago

What is the probability of meeting at least one person with the flu in 12 random encounters on campus when the infection rate is

Soloha48 [4]

Answer-

The probability of meeting at least one person with the flu in 12 is 0.3062 or 30.62%

Solution-

The probability of k successes in n trials where p is the probability of success on any given trial is given by,

$P(n;k,p)=\binom{n}{k}(p)^k(1-p)^{n-k}$

Here, 3 people out of 100 have the flu, so

$p=0.03$

As there are total 12 number of people, so

$n=12$

And

$P(\text{At least one flu})=1-P(\text{0 flu})$

The probability selecting 0 number of person with the flu out of 12 is,

$=\binom{12}{0}(0.03)^0(1-0.03)^{12-0}$

$=1\times 1\times(0.97)^{12}$

$=0.6938$

So, the probability of meeting at least one person with the flu in 12 is,

$=1-0.6938$

$=0.3062$

$=30.62\%$

3 0

3 years ago