Answer:
486
Step-by-step explanation:
just multiply and divide
8 x 27 / 4 x 9
The lowest possible product would be -5625 given the numbers 75 and -75.
We can find this by setting the first number as x + 150, which we see in the equation given above. The other number would have to be simply x since it has to have a 150 difference.
Next we'll multiply the numbers together.
x(x+150)
x^2 + 150x
Now we want to minimize this as much as possible, so we'll find the vertex of this quadratic graph. You can do this by finding the x value as -b/2a, where b is the number attached to x and a is the number attached to x^2
-b/2a = -150/2(1) = -150/2 = -75
So we know one of the values is -75. We can plug that into the equation to find the second.
x + 150
-75 + 150
75
Answer:
the number of hamburgers sold on Thursday were 325.
Step-by-step explanation:
The total number of hamburger and cheese burger is missing
i will replace it with any figure, you can replace it wit your given data and you will get the solution.
A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday
There were 57 fewer cheeseburgers sold than hamburgers
How many hamburgers were sold on thursday
Let h be the number of hamburgers and c be the number of cheeseburgers.
Using this information we can set up two equation as:

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

Therefore, the number of hamburgers sold on Thursday were 325.
The correct question is
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>