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Hunter-Best [27]

2 years ago

15

You have just arranged for a $1,800,000 mortgage to finance the purchase of a large tract of land. the mortgage has an apr of 7.

8 percent, and it calls for monthly payments over the next 30 years. however, the loan has an eight-year balloon payment, meaning that the loan must be paid off then. how big will the balloon payment be?

1 answer:

Marysya12 [62]2 years ago

6 0

Hey what is Apr? So I can help you with this; )

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One sprinter has a stride of 120cm, another 75cm. How many steps do they each take if they run a 100m race?

Olenka [21]

Answer:

1m = 100 cm

First sprinter stride is 120 cm. Steps he will take

= 100/1.2 = 83 1/3 steps

Second sprinter takes a stride of 75 cm

= 100/0.75 = 133 1/3 steps

3 0

3 years ago

drek231 [11]

The solutions to the inequalities are x >1 and x < 6

<h3>How to solve the inequalities?</h3>

The inequality expression is given as:

-2x + 5 < 3x + 10

Collect the like terms in the above inequality

-2x - 3x < 10 - 5

Evaluate the like terms

-5x < 5

Divide by -5

x >1

Also, we have

5(x - 2) <3x + 2

Open the bracket

5x - 10 < 3x + 2

Evaluate the like terms

2x < 12

Divide by 2

x < 6

Hence, the solutions to the inequalities are x >1 and x < 6

Read more about inequalities at

brainly.com/question/24372553

#SPJ1

5 0

1 year ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

For what value of g does the function f(g)=g2+3g equal 18

faust18 [17]

47 is the value of g

5 0

3 years ago

Read 2 more answers

Let u = (-1,3) and w (2,4) find the resulting vector of 2u-4w in component form

weqwewe [10]

The answer is A.(-10,-10)

7 0

2 years ago