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3 years ago

The lengths of the sides of a triangle are 12cm, 16cm, and 20cm. Is the triangle a right triangle?

Mathematics

1 answer:

sattari [20]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

To determine if the triangle is right

If the square of the longest side is equal to the sum of the squares on the other 2 sides then it is right.

longest side = 20 and 20² = 400

12² + 16² = 144 + 256 = 400

Thus the triangle is right

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Paladinen [302]

Take option 2.
Let n=2^30
Then:
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3 years ago

Elena and her grandfather both just had birthdays last week. The sum of their ages is 100 years. Her grandfather’s age is 4 time

ZanzabumX [31]

Answer:

Grandfather age = 20 * 4 = 80

Step-by-step explanation:

Let Elena age be x

grandfather age is 4x

x + 4x = 100

5x = 100

x = 100/5 = 20 = Elena age

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4 years ago

If M is in the interior of ∠RTD, m∠RTM = 40°, and m∠RTD = 65°, then m∠MTD = .

ASHA 777 [7]

Answer:

MTD = 75

Step-by-step explanation:

RTD + RTM + MTD = 180

65 + 40 + MTD = 180

105 + MTD = 180

Subtract 105 from both sides.

MTD = 75

Don't forget to mark me brainliest : )

4 0

3 years ago

I need help with this question.

klio [65]

The answer is E your welcome

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2 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago