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ivanzaharov [21]
3 years ago
13

The equation of line l is -3y+4x=9. Write the equation of a line that is parallel to line l and passes through the point (-12,6)

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line I is

-3y + 4x = 9

3y = 4x - 9

y = 4x/3 - 3

Comparing with the slope intercept form, slope = 4/3

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line passing through (- 12, 6) is - 3/4

To determine the y intercept, we would substitute m = - 3/4, x = - 12 and y = 6 into y = mx + c. It becomes

6 = - 3/4 × - 12 + c

6 = 9 + c

c = 6 - 9

c = - 3

The equation becomes

y = -3x/4 - 3

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Y - 3x = -8
y = 3x - 8...slope here is 3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/3.

y = mx + b
slope(m) = -1/3
(3,2)...x = 3 and y = 2
now we sub and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b

so ur perpendicular equation is : y = -1/3x + 3
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