Answer:
Yes you're right, it does
Answer:
reflection then translation
Step-by-step explanation:
you reflected of the y axis and then you translated 2 left and 5 up which brings you to 3
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,
A bakers dozen is 12 which would be $0.41 for each cookie. If you meant 13, it would be $0.38. All you have to do is divide 4.94 by the amount of cookies
Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).