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2 years ago

Can someone help please

Mathematics

2 answers:

den301095 [7]2 years ago

8 0

Answer

136

Explanation

The angles are altetnate

Temka [501]2 years ago

7 0

136 that us right because its going to be the same top and bottom and different on the sides

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Which of the following statements are true for a trapezoid?

Ugo [173]

The Best answer out of the answers above is option 3. A trapezoid has only 1 set of parallel sides.

Hope this Helps! ~Giz

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3 years ago

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Find the volume of the solid obtained by rotating the region bounded by the given curves about the speciﬁed axis. x+y = 3, x = 4

Ad libitum [116K]

The intersection between the curves are
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2 years ago

Can you help Jorge organize the results into a two-way frequency table? Please answer this ASAP

Juliette [100K]

Answer:

The table is attached!

Step-by-step explanation:

6 students play both musical instrument and a sport
3 students play neither a musical instrument nor a sport
14 students in total play a sport

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The frequency table thus is attached below:

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3 years ago

Lim (sin(pi/x)) as x tends to 0 from both sides

strojnjashka [21]

Hello from MrBillDoesMath!

Answer:

Limit does not exist.

Discussion:

The function 1/x has a vertical asymptote as x approaches 0 so

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2 years ago

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

1 year ago