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ad-work [718]
3 years ago
9

Select all the systems of equations that have exactly one solution.

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Step-by-step explanation:

y=3x+1, y= -3x+7

y=1,X=1

X+y=10,2x+2y=20

X=5, y=5

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Plz help 5 qeustions
patriot [66]
What 5 questions ? i would gladly help but i dont know what you want me to answer
8 0
3 years ago
if each bowl of ice crem creats a profit of $0.35 what could be the profit made from the 3/4 of a gallon of ice cream
Tanya [424]

each bowl of ice crem creats a profit of $0.35

For the profit made with 3/4 bowl of icecream : multiply 3/4 by $0.35

\begin{gathered} \text{ Profit for the }\frac{3}{4}\text{ bowl of icecream=}\frac{3}{4}\times0.35 \\ \text{ Profit for the }\frac{3}{4}\text{ bowl of icecream=}0.2625\text{ } \end{gathered}

Profit made by 3/4 bowl of icecream is $0.2625

5 0
1 year ago
Find sec theta if theta is in quadrant 4 and sin theta= -1/5
lara31 [8.8K]

Answer:

\frac{5}{2\sqrt{6} }

Step-by-step explanation:

Since Θ is in fourth quadrant then cosΘ > 0, as is secΘ

Given

sinΘ = - \frac{1}{5}, then

cosΘ = \sqrt{1-(-1/5)^2}

         = \sqrt{1-\frac{1}{25} } = \sqrt{\frac{24}{25} } = \frac{2\sqrt{6} }{5}

Hence

secΘ = \frac{1}{\frac{2\sqrt{6} }{5} } = \frac{5}{2\sqrt{6} }

5 0
3 years ago
Read 2 more answers
Shenelle has 100100100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of th
cluponka [151]
Area as a function of width, w is:
a(w)=(w-25)^2+625
for maximum area, the width will be:
a'(w)=2(w-25)+0=0
solving for w we egt
2w-50=0
2w=50
w=25 m
given that the perimeter is 100, the length will be:
100=2(L+W)
solving for L we get:
L=50-W
but W=25m
hence
L=50-25=25 m
thus the maximum area will be:
A=L*W=25*25=625m^2

8 0
3 years ago
Read 2 more answers
Find the least common multiple of: 12x^3y^2 and 15x^2y^5
allochka39001 [22]

Answer: 60x^3y^5

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: 12x^3y^2 and 15x^2y^5.

Since, 12x^3y^2=2\times2\times3\times x^3y^2

15x^2y^5=3\times5\times x^2y^5

The least common multiple of: 12x^3y^2 and 15x^2y^5. = 2\times2\times3\times5\times x^3y^5=60x^3y^5 [take highest power of x and y ]

Hence, the least common multiple of: 12x^3y^2 and 15x^2y^5. = 60x^3y^5

3 0
3 years ago
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