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3 years ago

14

If you are heading off to college discuss who will be paying for it, where you will live, what your intended major will be, and

how long to graduate. The remainder of your paper will focus on your newly held degree, the job opportunities in that field, prospects of getting a job, and finally what are the average STARTING salaries in the area of the country you are planning to live in.

1 answer:

Lilit [14]3 years ago

8 0

Answer:I think it’s telling you to discuss this stuff with your family, idt this is a question I can really answer

Step-by-step explanation:

You might be interested in

A rectangle has a heigh if 4x^3 and a width of x^3+3x^2+2x

Andrews [41]

Answer:

Area = $4x^6+12x^5+8x^4$

Step-by-step explanation:

<u>The Complete Question:</u>

A rectangle has height $4x^3$ and width $x^3+3x^2+2x$ . What is the area of the rectangle in terms of x?

<u>Solution:</u>

The formula for the area of a rectangle is:

Area = Height * Width

Both the expressions for height and width is given, so we just need to multiply both the expressions to get an expression, in x, for the area of the rectangle. The algebra is shown below:

$A=(4x^3)(x^3+3x^2+2x)\\A=4x^6+12x^5+8x^4$

This is the area of the rectangle.

8 0

3 years ago

____ [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 3x + x³

Taking differentiate

$\frac{d}{dx}\left(3x+x^3\right)$

$\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'$

$=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

solving

$\frac{d}{dx}\left(3x\right)$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'$

$=3\frac{d}{dx}\left(x\right)$

$\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1$

$=3\cdot \:1$

$=3$

now solving

$\frac{d}{dx}\left(x^3\right)$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}$

$=3x^{3-1}$

$=3x^2$

Thus, the expression becomes

$\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

$=3+3x^2$

Thus,

f'(x) = 3 + 3x²

Given that f'(x) = 15

substituting the value f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

15 = 3 + 3x²

switch sides

3 + 3x² = 15

3x² = 15-3

3x² = 12

Divide both sides by 3

x² = 4

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Thus, the value of x will be:

$x=2,\:x=-2$

5 0

3 years ago

Mathematical phrases

Reil [10]

Answer:

Sum

Difference

product

square root

Quotient

7 0

3 years ago

Read 2 more answers

Please help me I need ASAP

Sliva [168]

Answer:

(4) y=(x-3)²-4

I dont have much evidence to give

7 0

3 years ago

In 2014 Rose invested $16,000 in a savings account for her newborn son. The account pays 3.6% interest each year. Determine the

Juliette [100K]

Answer:

Total value of the account in 2032 will be $26,368

7 0

2 years ago