(2x-1)(2x-1)
(4x^2+2x+1)(2x-1)
(2x-1) cancels out so
2x-1
4^2+2x+1
Answer: Answer is D, if I'm not mistaking
Step-by-step explanation:
sorry if im wrong.
Answer:
The rule that represents the function is
therefore the function is 
Step-by-step explanation:
We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>
Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.
<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.
So <u>we propose the rule </u>
<u> which is correct for the first 3 values of x.</u>
Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as


Therefore, the rule is correct, and the function is

Answer:
19
Step-by-step explanation:
PEMDAS
no parenthesis
no exponents
4-6+2 x 7
4-6+ 17
no division
4-6=2
2+17
19 is the answer
Find the mean, median, mode, and range of the data 10, 13, 7, 6, 9, 4, 6, 3, 5
elena-s [515]
Median is 6 range is 9 mode is 6 and mean is 7