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frosja888 [35]
3 years ago
8

1. Write the decimal number in words. 4.837

Mathematics
2 answers:
andrey2020 [161]3 years ago
8 0

Answer:

Four point eight hundred-thirty seven

Delvig [45]3 years ago
3 0

Answer:

four and eight hundred thirty-seven thousandths

Step-by-step explanation:

You might be interested in
A town has a population of 17000 and grows at 2.5% every year. To the nearest year how long Will it be until The population will
Makovka662 [10]

Answer:

almost 15.5 years

Step-by-step explanation: let the population will be reached in t years

17000+(17000x2.5%xt) = 23600

or, 17000 x (1+ 2.5% x t) = 23600

or, 1+ 2.5% x t = 23600/17000

or, 1+ 2.5% x t = 236/170

or, 2.5% x t = 236/170 - 1

or, 2.5% x t = 66/170

or, t = 66/(170 x 2.5%)

t= 15.529

4 0
3 years ago
1. Suppose that the average outstanding credit balance for young couples is $650 with a standard deviation of $420. In an SRS of
Ganezh [65]

Answer:

11.70% probability that the mean outstanding credit balance exceeds $700

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 650, \sigma = 420, n = 100, s = \frac{420}{\sqrt{100}} = 42

In an SRS of 100 couples, what is the probability that the mean outstanding credit balance exceeds $700?

This is 1 subtracted by the pvalue of Z when X = 700. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{700 - 650}{42}

Z = 1.19

Z = 1.19 has a pvalue of 0.8830

1 - 0.8830 = 0.1170

11.70% probability that the mean outstanding credit balance exceeds $700

5 0
3 years ago
Reduce to lowest terms : 102/170
Fantom [35]

3/5 i believe///////////

8 0
3 years ago
Read 2 more answers
(4g^3-1) (3g-10) and show work please
REY [17]
Hello! And thank you for your question!

For this problem we can use the FOIL method/distributive method. 

Rewrite the equation to:

(4g³) + (-1)(3g) + (-10)

Then solve:

(4g³) times (3g¹) = 12g⁴

(4g³) times (-10) = -40g³

(-1) times (3g) = -3g

(-1) times (-10) = 10

Final Answer:

12g⁴ - 40g³ - 3g + 10
5 0
4 years ago
Can someone please help me with this question? Thanks.
forsale [732]

Answer:

f(x) = 3 + 5x

Step-by-step explanation:

For this problem, we can see a simple pattern whereas x increases by 1, y is increasing by 5.

This means that f(0) = 3.

And to create the function, we simply use f(0) summed with the increasing 5 multiplied by the input x.

Hence, we will create the function equation:

f(x) = 3 + 5x

Cheers.

3 0
4 years ago
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