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DaniilM [7]
3 years ago
8

X 16 28 44

Mathematics
1 answer:
Andrews [41]3 years ago
5 0

simple formula for that is y×2=x

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Find X<br> A. 11√3<br> B. 33<br> C. 44√2<br> D. 33√2
igor_vitrenko [27]

Answer:

  B.  33

Step-by-step explanation:

The side opposite the 45° angle has measure 11√6×sin(45°). The side opposite the 60° angle has measure tan(60°) times that, so we have ...

  x = 11√6×sin(45°)×tan(60°) = 11√6×(√2/2)×√3 = 11×(√6)²/2

  x = 33

_____

The mnemonic SOH CAH TOA can be a useful reminder of the definitions of the trig functions. It tells you ...

  Sin = Opposite/Hypotenuse

  Tan = Opposite/Adjacent

Using these relations, we can find the sides of interest:

  Opposite = Hypotenuse × Sin . . . . for the 45° triangle

  Opposite = Adjacent × Tan . . . . . . for the 60° triangle

where the side opposite the 45° angle is the side adjacent to the 60° angle.

5 0
3 years ago
What is 1 hour : 45 minutes in a ratio?
Afina-wow [57]
1 hour is 60 minutes. The ratio of 60 minutes to 45 minutes is 4:3 .
3 0
3 years ago
Find the quotient below. Write the answer as a fraction in simplest form. 1/3÷4 3/4Find the quotient below. Write the answer as
evablogger [386]

Answer:

Step-by-step explanation:

um

8 0
3 years ago
Helppppp! please show your work!
Shtirlitz [24]

Answer:

90 - 37 will give a solid 53

Step-by-step explanation:

the two sums of A to C to C to B so 22.9(C, B) and 14.1 (A, C)

and know that this angle is 90 degrees, my guess would be to subtract the to given numbers with degrees to earn the sum so 22.9 + 14.1 equals 37

now we add angle degrees and sum and subtract one another,

90 - 37

6 0
3 years ago
Three vertices of a parallelogram are shown in the figure below.
a_sh-v [17]

Given:

The three vertices of the parallelogram are (-3,9), (0,-3), (6,-6).

To find:

The fourth vertex of the parallelogram.

Solution:

Consider the three vertices of the parallelogram are A(-3,9), B(0,-3), C(6,-6).

Let D(a,b) be the fourth vertex.

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

We know that the diagonals of a parallelogram bisect each other. So, the midpoints of both diagonals are same.

Midpoint of AC = Midpoint BD

\left(\dfrac{-3+6}{2},\dfrac{9+(-6)}{2}\right)=\left(\dfrac{0+a}{2},\dfrac{-3+b}{2}\right)

\left(\dfrac{3}{2},\dfrac{3}{2}\right)=\left(\dfrac{a}{2},\dfrac{-3+b}{2}\right)

On comparing both sides, we get

\dfrac{3}{2}=\dfrac{a}{2}

3=a

And,

\dfrac{3}{2}=\dfrac{-3+b}{2}

3=-3+b

3+3=b

6=b

Therefore, the fourth vertex of the parallelogram is (3,6).

7 0
3 years ago
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