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3 years ago

Free 11 point, take it or leave it.

Mathematics

2 answers:

tekilochka [14]3 years ago

7 0

Answer:

thanks for the free points

Step-by-step explanation:

My name is Ann [436]3 years ago

3 0

Answer:

can i get brainest

Step-by-step explanation:

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In Cos A = 0.4 Find The Value Of Cos 3 A.<br><br><br><br>Thenku ☃️<img src="https://tex.z-dn.net/?f=%20%5C%3A%20%5C%3A%20" id="T

s2008m [1.1K]

Answer:
- 0.944

Step-by-step explanation:
We know that,
cos 3A = 4 cos³A - 3 cos A (formula)

So,
If cos A = 0.4,

cos 3A = 4 cos³A - 3 cos A
cos 3A = 4 × (0.4)³ - 3 × (0.4)
cos 3A = 4 × 0.064 - 1.2
cos 3A = - 0.944

Hope it helps ⚜

3 0

3 years ago

Read 2 more answers

Calcula el área de cada figura y con el resultado colorea el dibujo .Recuerda para obtener el área de un trapecio es (B+b)×a\2 p

ohaa [14]

Necesitamos las figuras... ;)

6 0

3 years ago

George is considering two different investment options. The first option offers 7.4% per year simple interest on the

jok3333 [9.3K]

Answer:

Part A: The value of the simple interest investment at the end of three years is $12,220

Part B: The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C: The simple interest investment is better over the first three years

Part D: I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Step-by-step explanation:

Part A:

A = P + P r t, where

A represents the value of the investment
P represents the original amount
r represents the rate in decimal
t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ First option offers 7.4% per year simple interest

∴ r = 7.4% = 7.4 ÷ 100 = 0.074

∵ He may not withdraw any of the money for three years after

the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ A = 10,000 + 10,000(0.074)(3)

∴ A = 10,000 + 2,220

∴ A = 12,220

The value of the simple interest investment at the end of three years is $12,220

Part B:

$A=P(1+\frac{r}{n})^{nt}$ , where

A represents the value of the investment
P represents the original amount
r represents the rate in decimal
n is a number of periods of a year
t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ The second option offers a 6.5% interest rate compounded quarterly

∴ r = 6.5% = 6.5 ÷ 100 = 0.065

∴ n = 4 ⇒ quarterly

∵ He may not withdraw any of the money for three years after

the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ $A=10,000(1+\frac{0.065}{4})^{(4)(3)}$

∴ $A=10,000(1.01625)^{12}$

∴ A = 12,134.08

The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C:

∵ 12,220 > 12,134.08

∴ The simplest interest investment is better than the compounded

interest investment at the end of three years

The simple interest investment is better over the first three years

Part D:

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Look to the attached graph below

The red line represents the simple interest investment
The blue curve represents the compounded interest investment
(Each 1 unit in the vertical axis represents $1000)
After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest
After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest