<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.
Answer:
It will take Will 12 days to read the whole book.
Step-by-step explanation:
36 ÷ 3
= 12
:))
Answer: About 43% of the paintings are displayed on the first floor.
Step-by-step explanation: For this problem we can use a percent equation to solve for p, the percent of paintings that will be displayed on the first floor.
Lets write the percent equation:
40/92 = p/100 (We basically are finding 40 out of 92 paintings is what percent of the total paintings.
40/92 x 100 = p/100 x 100 (We always multiply both sides by 100 when dealing with percent that are out of a whole, or 100.)
40 x 100 = 4000/92 = ABOUT 43. p/100 x 100 = p.
About 43 = p
So about 43% of the paintings are displayed on the first floor.
