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2 years ago

16% of 23 please helpppppp 1% of the same number is 4.6

Mathematics

1 answer:

adelina 88 [10]2 years ago

7 0

Answer:

3.68

Step-by-step explanation:

Make 16% a decimal then multiply by 23

.16*23=3.68

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Which equation does the graph below represent? y=1/3+x y=1/3x y=3+x y=3x

barxatty [35]

Lets find 2 points, one obvious one is (0,0), another point is (12,4)

$Slope = \frac{4-0}{12-0} =\frac{4}{12} = \frac{4\times 1}{4\times 3} = \frac{1}{3}$

y = mx + b

m is the slope

we got m = 1/3

We can eliminate answer choices C and D.

y = 1/3x + b

we need to solve for b

Plug in the point (0,0) and solve for b

0 = 1/3(0) + b

0 = 0 + b

b = 0

The equation of the line is y = 1/3x + 0, or y = 1/3x

Your answer is B.

3 0

3 years ago

Leroy's total job benefits were $50,150 last year. His total job expenses for traveling and for professional developement for th

kykrilka [37]

Answer:

A. $46,650

Step-by-step explanation:

Taking the first number of $50,150, we have to subtract his expenses. After subtracting Leroy's expenses, we get $46,650.

50150

- 3500

46650

7 0

3 years ago

Read 2 more answers

Can anyone help me solve 23, 24?

zimovet [89]

Answer:

Problem 23) $y=3x+6$

Problem 24) $y=-\frac{1}{3}x-5$

Step-by-step explanation:

step 1

Find the slope of the given line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$A(0,2)\ B(3,1)$

Substitute the values

$m=\frac{1-2}{3-0}$

$m=-\frac{1}{3}$

step 2

Problem 23

we know that

If two lines are perpendicular then the product of its slopes is equal to minus 1

$m1*m2=-1$

Find the slope of the line

we have

$m1=-\frac{1}{3}$

substitute in the equation and solve for m2

$(-\frac{1}{3})*m2=-1$

$m2=3$

with the slope m2 and the point $(0,6)$ find the equation of the line

Remember that

The equation of the line in slope intercept form is equal to

$y=mx+b$

we have

$m=3$

$b=6$ -----> the given point is the y-intercept

substitute

$y=3x+6$

step 3

Problem 24

we know that

If two lines are parallel, then its slopes are the same

with the slope m1 and the point $(0,-5)$ find the equation of the line

The equation of the line in slope intercept form is equal to

$y=mx+b$

we have

$m=-\frac{1}{3}$

$b=-5$ -----> the given point is the y-intercept

substitute

$y=-\frac{1}{3}x-5$

8 0

3 years ago

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

ElenaW [278]

$\huge\boxed{y-5&=-\frac{1}{3}(x+9)}$

First, we'll find the slope of the new line. The first line has a slope of $3$ . Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by $-1$ ) to get $-\frac{1}{3}$ for the new slope.