All categories

3 years ago

16% of 23 please helpppppp 1% of the same number is 4.6

Mathematics

1 answer:

adelina 88 [10]3 years ago

7 0

Answer:

3.68

Step-by-step explanation:

Make 16% a decimal then multiply by 23

.16*23=3.68

You might be interested in

A pyramid has a square base with side s. The height of the pyramid is 2/3 that of its side. What is the expression for the volum

Alona [7]

<span>I think the height is 2/3 that of a side of the base. If that is correct, then the height is h = 2/3s.

The formula for the volume of a pyramid is \[V=\frac{ 1 }{ 3 }s ^{2}h\]

Normally it would be B for base area, but since this is a square and the height is in terms of s, that would be the formula.

If we find the area based on the fact that h = 2/3s, then it appears that the formula would be

V=1/3s^2 x 2/3s

If you multiply that all out, it would be V= 2 / 9s ^3
</span>

3 0

3 years ago

Read 2 more answers

The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s. At

musickatia [10]

Answer:

Volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

Step-by-step explanation:

Given: The radius of a right circular cone is increasing at a rate of $1.9$ in/s while its height is decreasing at a rate of $2.2$ in/s.

To find: The rate at which volume of the cone changing when the radius is $134$ in. and the height is $136$ in.

Solution:

We have,

$\frac{dr}{dt} =1.9 \:\text{in/s}$ , $\frac{dh}{dt}=-2.2\:\text{in/s}$ , $r=134 \:\text{in}$ , $h=136\:\text{in}$

Now, let $V$ be the volume of the cone.

So, $V=\frac{1}{3}\pi r^{2}h$

Differentiate with respect to $t$ .

$\frac{dv}{dt} =\frac{1}{3}\pi \left [ r^2\frac{dh}{dt}+h\left ( 2r \right )\frac{dr}{dt} \right ]$

Now, on substituting the values, we get

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ \left ( 134 \right )^2\left ( -2.2 \right )+\left ( 136\right )\left ( 2 \right )\left ( 134 \right )\left ( 1.9 \right ) \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ -39503.2+69251.2 \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ 29748 \right ]$

$\frac{dv}{dt} =9916\pi \frac{in^3}{s}$

Hence, the volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

6 0

3 years ago

Can someone help me with this? Thanks! :)

melomori [17]

Answer:

$\huge\boxed{c)\ 15,\ 36,\ 39}$

Step-by-step explanation:

$\text{Let}\ a\leq b\leq c\ \text{the sides of the triangle}.\\\\\text{If}\ a^2+b^2=c^2\ \text{then a triangle is a right triangle}\\\\\text{If}\ a^2+b^2c^2\ \text{then a triangle is a acute triangle}$

$a)\ 28,\ 45,\ 53\\\\28^2+45^2=784+2025=3593\\53^2=2809\\\\28^2+45^2>53^2\to\text{acute triangle}\\\\b)\ 17,\ 22,\ 29\\\\17^2+22^2=289+484=773\\29^2=841\\\\17^2+22^2$