Answer:
70-79
Step-by-step explanation:
since there is more data or a bigger block and that is what mode is the mode would be the one that shows up the most in the data set.
3 and four sevenths bcs 25divided by seven is 3r4
a^2 + b^2 = c^2
a = sqrt(c^2 - b^2) = sqrt (20^2 - 16^2)
= 12
sin
= a/c = 12/20
= 3/5
cos = b/c = 16/20
= 4/5
tan = a/b = 12/16
= 3/4
csc
= c/a = 20/12
= 5/3
= 1 2/3
sec = c/b = 20/16
= 5/4
= 1 1/4
It is not because the figure only has 2 hexagons (top and bottom) but the net has 3. So, your answer is NO.
