Which statement is true?

What is the value of x in the equation three-fourths (one-fourth x 8) minus (one-half x 2) = startfraction 3 over 8 endfraction

Oksi-84 [34.3K]

The value of x in the equation is x=-44.

The given equation is $\frac{3}{4}\left(\frac{1}{4}x+8\right)-\left(\frac{1}{2}x+2\right)=\frac{3}{8}(4-x)-\frac{1}{4}$ .

An algebraic expression in mathematics is an expression that's made from variables and constants, together with algebraic operations (addition, subtraction, etc.). Expressions are made of terms.

Firstly, apply the distributive property as a(b+c)=ab+ac and get

$\begin{aligned}\frac{3}{4}\times \frac{1}{4}x+\frac{3}{4}\times 8-\frac{1}{2}x-2&=\frac{3}{8}\times 4-\frac{3}{8}\times x-\frac{1}{4}\\ \frac{3x}{16}+6-\frac{x}{2}-2&=\frac{3}{2}-\frac{3x}{8}-\frac{1}{4} \end$

Now, rearrange the terms by taking variable terms on the left-hand side and constant terms on the right-hand side as

$\frac{3x}{16}-\frac{x}{2}+\frac{3x}{8}=\frac{3}{2}-\frac{1}{4}-6+2$

Further, simplify the above expression by taking L.C.M as

$\begin{aligned}\frac{3x-8x+6x}{16}&=\frac{6-1}{4}-4\\ \frac{x}{16}&=\frac{5-16}{4}\\ \frac{x}{16}&=\frac{-11}{4}\end$

Then, multiply both sides with 4 and get

$\begin{aligned}4\times \frac{x}{16}&=4\times \frac{-11}{4}\\ \frac{x}{4}&=\frac{-11}{1}\end$

Furthermore, cross multiply both sides and get

$x=-44$

Hence, the value of x in the equation which is given $\frac{3}{4}\left(\frac{1}{4}x+8\right)-\left(\frac{1}{2}x+2\right)=\frac{3}{8}(4-x)-\frac{1}{4}$ is x=-44.

Learn about algebraic expression from here brainly.com/question/8690932

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