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Reil [10]
3 years ago
8

25/7 as a mixed number

Mathematics
2 answers:
Aleks [24]3 years ago
7 0
3 and four sevenths bcs 25divided by seven is 3r4
Tema [17]3 years ago
4 0


just divide the numerator by the denominator;

25 ÷ 7 =  3 4/7

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She use 17 1 4 cups of sugar and needs another 7 8 cups for other batch how many cups will she use alltogether
kvasek [131]
What you want to do is find the greatest common denominator, so for now put the 17 to the side and focus on the 1/4 and 7/8, we can find the GCD (greatest common denominator) by multiplying 1/4 • 8/8 = 8/32 And then multiplying 7/8 • 4/4 = 28/ 32 So here we have remaining 17 & 8/32 cups PLUS 28/32 cups, you can add the numerators straight across and keeps the denominators the same, which says that she uses 18 & 4/32
Simplified version: 18 & 1/8
6 0
3 years ago
(3 + 4i) + (5 − 2i) (2 points) −2 + 6i 2 − 2i 7 + 3i 8 + 2i
k0ka [10]

Answer:

8+2i

Step-by-step explanation:

Combine like terms

3+5=8

4i-2i=2i

6 0
3 years ago
5/8 of the cats perferred drinking with there tongue but 3/16 wanted a straw if there was 39 cats that gave one of these 2 answe
AveGali [126]

Answer:

208cats

Step-by-step explanation:

⅝=tongue

³/16=straw=39cats

⅝+³/16=13/16

meaning total number of cats is 16/16

If ³/16=39cats

16/16=?

39×16/3

=208cats

6 0
3 years ago
Are 4/16 and 0.25/2 equivalent numbers? If so, explain how they are.
Aleksandr-060686 [28]
Two fractions are equivalent if the product of the numerator of the first and the denominator of the second is equal to the product of the numerator of the second and the denominator of the first.
                           4 x 2 ___ 16 x 0.25
                               8 is not equal to 4
Thus, they are not equivalent. 
3 0
3 years ago
Find the equation of the line containing the points (20,-7) and (10,-2). Type your answer in this order and don't use spaces or
aliina [53]

(\stackrel{x_1}{20}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{20}}}\implies \cfrac{-2+7}{-10}\implies -\cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{1}{2}}(x-\stackrel{x_1}{20}) \\\\\\ y+7=-\cfrac{1}{2}x+10\implies y=-\cfrac{1}{2}x+3

4 0
2 years ago
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