How many protons, neutrons, and electrons does Al^3+ have?

How many structures are possible for a trigonal bipyramidal molecule with a formula of ax3y2?

ryzh [129]

Check the attached file for the answer.

4 0

3 years ago

The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi

galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

<u>Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.</u>

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}$

So,

Moles of Nitric acid = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

$moles=\frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ Nitric\ acid=Moles \times Molar mass}$

$Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}$

<u>Mass of Nitric acid = 116.55 g</u>

Also,

$Density=\frac{Mass}{Volume}$

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

$Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}$

$Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}$

<u>Mass of the solution = 1640 g</u>

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

$Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}$

So,

$Mass \%=\frac{116.55}{1640} \times {100}$

6 0

3 years ago

For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono

mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

$2NO(g) +2H_2(g)$ → $N_2 +2H_2O$

Moles of nitrogen monoxide

Molecular weight: $M_(_N_O_)$ =30g/mol

$n_(_N_O_) =\frac{mass}{molar \;mass}$

$n_(_N_O_) =\frac{22.0}{30g/mol}$

$n_(_N_O_) = 0.73 mol$

Moles of hydrogen

Molecular weight: $M_(_H_2_)$ =30g/mol

$n_(_H_2_) =\frac{mass}{molar \;mass}$

$n_(_H_2_) =\frac{5.80g}{2g/mol}$

$n_(_H_2_) = 2.9 mol$

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

$n_(_N_2_) =$ (2.9 mol- 0.73 mol NO x $\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}$ ) x $\frac{2g \;of \;H_2}{mole \;of \;H_2}$

$n_(_N_2_) =$ 4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

5 0

2 years ago

In the context of the 4ps of the marketing mix, high-tech media options like cell phones and the internet have had a huge impact

mina [271]

In the context of the 4ps of the marketing mix, high-tech media options like cell phones and the internet have had a huge impact on products.

The four Ps represent the crucial factors that must be carefully thought out and put into practice in order to properly advertise a good or service. Product, price, place, and promotion make up this list.

The marketing mix is another name for the four Ps. They cover a wide range of aspects that are taken into account when marketing a product, such as what consumers want, and how the good or service satisfies or doesn't satisfy those wants.

Also on how the good or service is perceived in society, and how it distinguishes itself from the competition, and how the business that makes it engages with its clients.

To learn more about marketing mix refer to:

brainly.com/question/14591993

#SPJ4

8 0

1 year ago

How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?

Katarina [22]

Answer:

159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.

Explanation:

How many grams of LiNO2 are required to make 250 mL of 0.75 M?

First calculate the molarity in mol per dm3

0.75 M of LiNO2 reacts in 250 mL = 250 /1000 L volume

0.75 M = 0.25 L

In 1 L, the molarity of LiNO2 will be:

= (0.75 * 1/ 0.25) M

= 3 mol/dm3 of LiNO2

Next is to calculate the molarity in g/dm3:

Molarity in mol/dm3 = molarity in g/dm3 / RMM.

RMM of LiNO2

(Li = 7 , N =14 , 0 = 16)

RMM = ( 7 + 14 + 16 * 2) = 53 g/mol

Molarity in mol/dm3 = Molarity in g/dm3 / RMM

Molarity in g/dm3 = Molarity in mol/dm3 * RMM

Molarity in g/dm3 = 3 * 53

Molarity in g/dm3 = 159 g/dm3.

So therefore, to make 250 mL of 0.75 M of LiNO2, we use 159 grams of LiO2.

8 0

3 years ago