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3 years ago

The electron configuration belonging to the atom with the highest second ionization energy is ________.

Chemistry

1 answer:

Gemiola [76]3 years ago

5 0

Answer:

Element Lithium

Explanation:

The element with the highest second ionization energy is lithium. It belongs to the alkaline metal group I.e group one metals

It has the highest second ionization energy because it is very difficult to remove the electron from the 1s orbital.

Its atomic number is 3. The electronic configuration is 1s2 2S1

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If measuring experimental results, what can you predict about the work output of a 1200 watt hair dryer? the work output of the

eimsori [14]

Answer: first option, the work output of the hairdryer will be less than the work input.

Explanation:

1) The work output measured in watts is the power of hair dryer measured in joules per second.

2) The hair dryer converts electrical energy from the wall outlet to mechanical and thermal energy: hot wind.

3) Nevertheless, you can never expect a 100% efficiency of the machines: due to friction, some energy is converted into useless energy.

So, efiiviency = power output / power input< 1 ⇒

power output = work output / time

input power = work input / time

⇒ work output / work input < 1

⇒ work output < work input.

Which is the first option: the work output of the hairdryer will be less than the work input

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3 years ago

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Refer to the example about diatomic gases A and B in the text to do problems 19 - 27.

soldier1979 [14.2K]

Answer:a

Explanation:

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3 years ago

How is the number of unpaired valance electrons in an atom related to the number of bonds that the atom can form?

TiliK225 [7]

It is the same amount. For example, Carbon has 4 electrons. Putting those 4 electrons in a Lewis Dot Structure will show that they are not paired, so 4 is the number of bonds Carbon can make.

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3 years ago

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO 3 ( s ) + 2

e-lub [12.9K]

Answer: The mass of calcium chloride formed is 15.21 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For calcium carbonate:

Given mass of calcium carbonate = 32.0 g

Molar mass of calcium carbonate = 100 g/mol

Putting values in equation 1, we get:

$\text{Moles of calcium carbonate}=\frac{32.0g}{100g/mol}=0.32mol$

For hydrochloric acid:

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol$

The given chemical equation follows:

$CaCO_3(s)+2HCl(aq.)\rightarrow CaCl_2(aq.)+H_2O(l)+CO_2(g)$

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium carbonate

So, 0.274 moles of hydrochloric acid will react with = $\frac{1}{2}\times 0.274=0.137mol$ of calcium carbonate

As, given amount of calcium carbonate is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.274 moles of hydrochloric acid will produce = $\frac{1}{2}\times 0.274=0.137moles$ of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 111 g/mol

Moles of calcium chloride = 0.137 moles

Putting values in equation 1, we get:

$0.137mol=\frac{\text{Mass of calcium chloride}}{111g/mol}\\\\\text{Mass of calcium chloride}=(0.137mol\times 111g/mol)=15.21g$

Hence, the mass of calcium chloride formed is 15.21 grams.

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3 years ago

What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?

Vlad1618 [11]

What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?

Na2CO3

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3 years ago

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