Answer:
Keisha =$25
Scott =$19
Ryan = $57
Step-by-step explanation:
Let the amount each have be represented by A, B and C
Keisha = A
Scott = B
Ryan = C
Keisha , Scott and Ryan have a total of $101.
That’s
A + B + C = $101
Keisha has $6 more than Scott
A = 6 + B
Ryan has 3 times Scott
C = 3B
Substitute 6+B for A and 3B for C in the first equation.
That’s
A + B + C = 101
6 + B + B + 3B = 101
6 + 5B = 101
Subtract 6 from both sides
6 - 6 + 5B = 101 - 6
5B = 95
Divide both sides by 5
B = 95/5
B = 19
Scott has $19
Recall Keisha has $6 more than Scott B.
That’s A = 6 + B
A = $6 + $19
A = $25
Keisha has $25
Also, Ryan C has 3 times what Scott B has .
That’s
C = 3 x B
C = 3 x 19
C = $57
Therefore, Keisha has $25, Scott has $19 and Ryan has $57
Answer:
95.4
Step-by-step explanation:
I believe you are referring to this equation: (9u-11)/2 = (19u +11)/3. To solve this step-by-step, first, multiply each side by 6 which is the least common denominator of 2 and 3. This then results to: 27u - 33 = 38u + 22. Second, combine like terms on one side such that: 11u = -55. Finally, the value for u is calculated to be -5.
Answer:

In order to find the variance we need to find first the second moment given by:

And replacing we got:

The variance is calculated with this formula:
![Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%200.33%20-%280.15%29%5E2%20%3D%200.3075)
And the standard deviation is just the square root of the variance and we got:

Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X
X 0 1 2 3
P(X) 0.92 0.03 0.03 0.02
We can calculate the expected value with the following formula:

And replacing we got:

In order to find the variance we need to find first the second moment given by:

And replacing we got:

The variance is calculated with this formula:
![Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%200.33%20-%280.15%29%5E2%20%3D%200.3075)
And the standard deviation is just the square root of the variance and we got:

Answer:
90
Step-by-step explanation: