Step-by-step explanation:
The distance formula between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Substitute the coordinates of the points.
![A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}](https://tex.z-dn.net/?f=A%284%2C%5C%200%29%2C%5C%20B%282%2C%5C%201%29%2C%5C%20C%28-1%2C%5C%20-5%29%5C%5C%5C%5CAB%3D%5Csqrt%7B%282-4%29%5E2%2B%281-0%29%5E2%7D%3D%5Csqrt%7B%28-2%29%5E2%2B1%5E2%7D%3D%5Csqrt%7B4%2B1%7D%3D%5Csqrt5%5C%5C%5C%5CAC%3D%5Csqrt%7B%28-1-4%29%5E2%2B%28-5-0%29%5E2%7D%3D%5Csqrt%7B%28-5%29%5E2%2B%28-5%29%5E2%7D%3D%5Csqrt%7B25%2B25%7D%3D%5Csqrt%7B50%7D%5C%5C%5C%5CBC%3D%5Csqrt%7B%28-1-2%29%5E2%2B%28-5-1%29%5E2%7D%3D%5Csqrt%7B%28-3%29%5E2%2B%28-6%29%5E2%7D%3D%5Csqrt%7B9%2B36%7D%3D%5Csqrt%7B45%7D)
If a ≤ b < c are the sides of the right triangle, then
a² + b² = c²
![\sqrt5](https://tex.z-dn.net/?f=%5Csqrt5%3C%5Csqrt%7B45%7D%3C%5Csqrt%7B50%7D%5C%5C%5C%5C%28%5Csqrt5%29%5E2%2B%28%5Csqrt%7B45%7D%29%5E2%3D5%2B45%3D50%5C%5C%5C%5C%28%5Csqrt%7B50%7D%29%5E2%3D50%5C%5C%5C%5C%5Cbold%7BCORRECT%7D)
used
for a ≥ 0.
therefore ΔABC is a right triangle.
First you have to get the number on the right 40 to equal 100 so do 40x2=80- +40x1.5= 100
Then do the same thing to the first number 8 so 8x2=16+8x1.5=20
then you have 20/100 right so then that number over 100 is the percent that you get ^-^ 20%
I guess any ten pounds can be the same weight as light stuffs combined together such as multiple breaks, a school bag, etc.
Answer:
The answer is B
Step-by-step explanation:
To find the area of a parallelogram you need to multiply base by height
In this problem the base is 67 square ft and the height is 52 square feet 67 times 52 = 3484
<span>A. It was the diethylene glycol the drug was put into so it could be given in liquid form that killed people, not the drug</span>