Question

What number should you subtract from the numerator of the fraction 52367/47633 and add to the denominator so that, after reducing, you get 17/38
Equation needed too!

Answer 1

Let $x$ be the number that you should subtract from the numerator of the fraction 52367/47633 and add to the denominator so that, after reducing, you get 17/38.
$\frac{52367-x}{47633+x} = \frac{17}{38}$
$38(52367-x)=17(47633+x)$
$1989946-38x=809761+17x$
$1180185=55x$
$x= \frac{1180185}{55}$
$x= \frac{236037}{11}$

We can conclude that the number you should subtract from the numerator of the fraction 52367/47633 and add to the denominator so that, after reducing, you get 17/38 is:$\frac{236037}{11}$