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kari74 [83]
2 years ago
8

You are testing two food scales for accuracy by weighing two different types of foods. Use the drop-down menus to complete the s

tatements about the scales' accuracy. Scale 1 Measured Weight Actual Weight 85 oz 100 oz Scale 2 Measured Weight Actual Weight 47 oz 50 oz CLEAR CHECK Because the object on Scale 1 weighs more than the object on Scale 2, each ounce of error results in a lesser percent error. Scale 1 was 15 ounces off and Scale 2 was 3 ounces off, so Scale 1 was % off and Scale 2 was % off.
Mathematics
1 answer:
Komok [63]2 years ago
4 0

Answer:

scale 1 was 15% off and SCALE 2 was 6% off

Step-by-step explanation:

Scale __ Measured Weight ____Actual Weight

1_________85 oz _______________100 oz

2 ________ 47 oz _______________ 50 oz

Percentage error :

[(|measured - actual |) ÷ actual] * 100%

Scale 1 :

|85 - 100| = 15 oz

15 / 100 * 100% = 15%

Scale 2 :

|47 - 50| = 3 oz

3 / 50 * 100% = 0.06 * 100% = 6%

Hence, scale 1 was 15% off while SCALE 2 was 6%

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3 years ago
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Step-by-step explanation:

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

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=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

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 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

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