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sveticcg [70]
3 years ago
11

Solve the following inega) x² - 5x +4> 02​

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0

Answer:

Inequality form: x<1 or x>4

Interval Notation:

(-∞,1)∪(4,∞)

I hope this helps you

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julsineya [31]
I got 16 but not 100% sure if it’s right
Sorry if it’s wrong, I tried my best
8 0
3 years ago
Given: f(x)=x^(2)-3 and g(x)=x+1 the composite function g*f is
Ivenika [448]

Answer:

<h2>x³ + x² - 3x - 3</h2>

Step-by-step explanation:

I'm assuming g*f means g times f,  so you want to multiply the two functions together.  

(x² - 3)(x + 1)                 Since the product is 2 binomials, use FOIL

                      =  x²(x) + x²(1) - 3(x) - 3(1)

which simplifies to

<h2>x³ + x² - 3x - 3</h2>
8 0
3 years ago
Read 2 more answers
Scientific notation 100400
ad-work [718]
1.004 * 10^5
all scientific notation equations have to be a number greater than 1 but less than 10
then multiplied by 10 to the power of (move the decimal point to the right however many times you need, in this case 5) :)
5 0
4 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
4 years ago
Read 2 more answers
Answer 2. will give brainliest
postnew [5]

Answer:

I think c and d

Step-by-step explanation:

srry if im wrong

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