What is the lateral surface of the prism shown here

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

5 0

Answer:

The lateral surface area of the prism shown is 1021 unit^2.

Step-by-step explanation:

2((21*9)/2) + (17*16) + (21*16) + (14*16) = <u>1021 unit^2</u>

evablogger [386]3 years ago

3 0

Answer: The lateral surface area of a prism is the sum of the areas of its lateral faces. The total surface area of a prism is the sum of the areas of its lateral faces and its two bases

=ph where p represents the perimeter of the base and h represents the height of the prism.

You might be interested in

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$