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2 years ago

Two sides of an isosceles triangle measure 3 inches and 7 inches. Which could be the length of the third side?

Mathematics

1 answer:

slamgirl [31]2 years ago

6 0

Answer:

Step-by-step explanation:

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X^4-28x^2=0 solve algebraically

Paha777 [63]

$x^4 - 28x^2 = 0$

$x^2(x^2 - 28) = 0$

$x^2 = 0 \ \ or \ \ (x^2 - 28) = 0$

$x = 0 \ \ or \ \ x^2 = 28$

$x = 0 \ \ or \ \ x = \pm \sqrt{28}$

$x = 0 \ \ or \ \ x = \pm2 \sqrt{7}$

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Answer : x = 0 or 2√7 or -2√7
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8 0

3 years ago

If ΔABC ≌ ΔRPQ , ∠A = 35˚, ∠C=75˚ , Find the measure of ∠Q. *

Norma-Jean [14]

<h3>Answer: angle Q = 75 degrees</h3>

Explanation:

The order of ABC and RPQ is important so we can match up the angles like so

angle A = angle R .... first letters
angle B = angle P .... second letters
angle C = angle Q ... third letters

Meaning that angle Q = 75 since angle C is this measure.

3 0

3 years ago

Read 2 more answers

One third of a number reduced by 11 is equal to 4 more than the number

Alecsey [184]

1/3x -11 = 4+x is what we start with, then add 11 to both sides, then subtract x from both sides. Then when we divide both sides by -2/3, x will equal -22.5.

6 0

3 years ago

Write the equation x² + 6x + y² – 8y = 19 in standard form.

kirza4 [7]

Answer:

Formula used :

x²+2xy+y² = (x+y)²
x²-2xy+y² = (x-y)²

$→{x}^{2} + 6x + {y}^{2} - 8y = 19 \\ ({x}^{2} + 2.3.x + {3}^{2} ) +({y}^{2} - 2.4.y + {4}^{2} ) = 19 + {3}^{2} + {4}^{2} \\ {(x + 3)}^{2} + {(y - 4)}^{2} = 19 + 9 + 16 \\ \boxed{ {(x + 3)}^{2} + {(y - 4)}^{2} = 44}✓$

3) (x+3)²+(y-4)²=44 is the right answer.

8 0

3 years ago

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Select the quadratic that has roots x = 8 and x = -5.

Mars2501 [29]

$\text{ The roots are}~ \alpha = 8~ \text{and}~ \beta = -5\\\\\text{Equation for the given roots,}\\\\x^2 -(\alpha +\beta )x +\alpha \beta = 0\\\\\implies x^2 -(8-5)x + 8(-5)=0\\\\\implies x^2 -3x -40=0\\\\\text{Hence, the answer is option B}$

6 0

2 years ago