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Mariulka [41]
3 years ago
7

Find the missing variables

Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Answer:

x = (x +10)(x- 10) - 3 + -10 = -13

Step-by-step explanation:

x = - 13

This is the best I can do for now. I am tired

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The measure of the angles of a triangle are represented by 2x + 15, x + 20, and 30 + 25. Find the measure of the smallest angle
ss7ja [257]
2x+15+x+20+30+25=180
3x+90=180
x=90/3
x=30
New angles
75,50,55
The smallest angle is 50
4 0
3 years ago
Johnston Road 1.05 miles on Friday 1.5 miles on Saturday 1.25 miles on Monday and 1.1 miles on Tuesday on what day did he ride t
IRISSAK [1]
He rode the shortest distance on Friday.
5 0
3 years ago
Read 2 more answers
Numarul 4 este solutie a ecuatiei 3(x-1)=5+x
sweet-ann [11.9K]
To solve x, you would distribute the 3 to the numbers in the parenthesis. 3x-3=5+x Now you would combine like-terms which would give you: 2x=2. Now you would divide by 2 on both sides to give you x=1. I hope you understand what I did. Hope I helped you!
7 0
3 years ago
If a gambler places a bet on the number 7 in​ roulette, he or she has a​ 1/38 probability of winning.
SCORPION-xisa [38]
A) The mean would be 1.842 and the standard deviation would be 1.339.
b) It would not be unusually low.

Explanation
a) This can be modeled as a binomial distribution, since there are two outcomes (7 or not 7), the events are independent (getting a 7 on one spin does not influence the chance of a 7 on the next spin) and there are a fixed number of trials (70).  In a binomial distribution, the mean is given by n*p, where n is the number of trials and p is the probability.

μ=n*p=70*(1/38) = 1.842.

The standard deviation of a binomial distribution is given by
σ=√(n*p*(1-p))=√(70(1/38)(37/38)=1.339.

b) To determine if this is unusually low, we find the probability:
_nC_k\times p^n\times (1-p)^{k-n}
\\
\\=_{70}C_0\times (\frac{1}{38})^0\times \frac{37}{38}^{70}
\\
\\=0.15

Since this is not below 0.05, we do not consider this unusual.
3 0
4 years ago
In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos(A)?
kotegsom [21]
Use the cosine rule.
c=AB=7
b=AC=8
a=BC=3
a^2=b^2+c^2-2bc(cos(A)) 
=>
cos(A)=(b^2+c^2-a^2)/(2bc)
=(7^2+8^2-3^2)/(2*7*8)
=13/14
=0.9286
6 0
3 years ago
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