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Mashutka [201]
3 years ago
7

Manny observed a Northern Gannet, a deep diving seabird, hovering at a height of 10 meters above the ocean surface. The bird the

n dove into the water, diving to a depth of 16 meters before coming to the surface. The dive can be modeled by a quadratic function, y = x2 – 10.3x + 10, where x represents the time the dive lasted in seconds and y represents the height of the bird in meters. Use the graphing calculator to graph the equation. After how many seconds did the bird surface? Round your answer to the nearest tenth.

Mathematics
2 answers:
mr Goodwill [35]3 years ago
8 0

Answer:

9.2 seconds.

Step-by-step explanation:

We have been given an equation that represents dive of a bird as y=x^2-10.3x+10, where x represents the time the dive lasted in seconds and y represents the height of the bird in meters.

We can see that our given equation is a parabola. The leading coefficient is positive, so our parabola will be an upward opening parabola.

Upon graphing our given equation, we will get our required graph as shown in the attachment.

As x represents the time the dive lasted in seconds and y represents the height of the bird in meters, so the bird will be at the surface when the graph will cross x-axis.

We can see that graph crosses x-axis at x=1.085\text{ and }x=9.215.

Upon rounding to nearest tenth, we will get:

x\approx 1.1\text{ and }x=9.2.

At x\approx 1.1 the bird dives in water and goes down the water surface and at x=9.2 the bird comes to the surface, therefore, the bird will be at surface after 9.2 seconds.

leva [86]3 years ago
5 0

Answer:

9.2 sec

Step-by-step explanation:

Did the assignment.

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Step-by-step explanation:

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3 years ago
The number of people attending the first basketball game of the season was 840. The number of people attending the last game of
melamori03 [73]

Answer:

Step-by-step explanation:

percent increase = (new number - original number) / (original number) * 100

                             = (1200 - 840) / (840) * 100

                             = (360) / 840 * 100

                              = 0.4285 * 100

                              = 42.85% rounded to nearest percent = 43% <==

5 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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Answer:

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Step-by-step explanation:

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3 years ago
Rectangle EFGH is similar to rectangle JKLM. Which proportion can be used to
Dominik [7]

*See attached picture for the diagrams being referred to

Answer:

C. ⁵/12= ²/x

Step-by-step Explanation:

Given that rectangle EFGH is similar to rectangle JKLM, it means the corresponding sides of both rectangles are similar, and as such the ratios if the corresponding sides of rectangle EFGH and rectangle JKLM would be equal.

Thus, EF/JK = FG/KL

Since, EF = 5; JK = 12; FG = 2; and KL= x, therefore, the proportion to use in finding x would be:

⁵/12= ²/x

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