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2 years ago

Juan picked 12 oranges. Rami picked 4 times as many oranges as Juan. How many oranges did Rami pick?

Mathematics

2 answers:

natka813 [3]2 years ago

8 0

Answer: it's simple what does 12x4 equal? 48 so your ANSWER: is 48

Simora [160]2 years ago

3 0

Rami picked 16 oranges

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Write the equation of the line parallel to 2x - 6y = 12 that passes through the point ( -1, 4).

vlada-n [284]

Answer:

y = 1/3x + 4 1/3

Step-by-step explanation:

2x - 6y = 12

First find the slope

Solve for y

Subtract 2x

2x - 6y -2x= 12-2x

-6y = -2x+12

Divide by -6

-6y/-6 =-2x/-6 +12/-6

y = 1/3 x -2

The slope is 1/3

Parallel lines have the same slope

Using the slope intercept form y = mx+b where m is the slope and b is the y intercept

y = 1/3x +b

And substituting in the point

4 = 1/3 (-1) +b

4 = -1/3 +b

Add 1/3 to each side

4 + 1/3 = b

y = 1/3x + 4 1/3

4 0

3 years ago

A hula hoop has an circumference 150.72 cm. What is the area of the hula hoop? (round to the nearest hundredth)

Leya [2.2K]

Answer:

Area = 1808.64 cm

Step-by-step explanation:

Circumference of a circle = 2πr

Circumference = 150.72

π = 3.14

r = radius

150.72 = 2 x 3.14 x r

150.72 = 6.28 r

r = 150.72/6.28

r = 24cm

Radius = 24

Area of a circle = πr²

Area = 3.14 x 24²

Area = 3.14 x 576

Area =1808.64 cm

6 0

2 years ago

What are the restrictions for a? 2a^2+a-15/5a^2+16a+3

koban [17]

ANSWER

The restrictions are

$a\ne -3,a\ne -\frac{1}{5}$

EXPLANATION

We were given the rational function,

$\frac{2a^2+a-15}{5a^2+16a+3}$

The function is defined for all values of a, except

$5a^2+16a+3=0$

This has become a quadratic trinomial, so we need to split the middle term.

We do that by multiplying the coefficient of $x^2$ which is 5 by the constant term which is 3. This gives us 15.

The factors of 15 that adds up to 16 are 1 and 15.

We use these factors to split the middle term.

$5a^2+15a+a+3=0$

We now factor to get,

$5a(a+3)+1(a+3)=0$

We factor further to get,

$(a+3)(5a+1)=0$

This implies that,

$(a+3)=0,(5a+1)=0$

This gives

$a=-3,a=-\frac{1}{5}$

These are the restrictions.

8 0

3 years ago

ACDE was translated down and right to form triangle

babymother [125]

Answer:the correct answer is ab,ef

Step-by-step explanation:

1,2,5,6 just took test

5 0

2 years ago

I need help with this promblem it’s ALGEBRA 2!

AlekseyPX

Answer:

$(f\circ h)(2)=2$

Step-by-step explanation:

<u>Composite Function </u>

Given f(x) and h(x) real functions, the composite function named $(f\circ h)(x)$ is defined as:

$(f\circ h)(x)=f(h(x))$

It can be found by substituting h into f.

We are given the functions:

$f(x)=2x^2-9x+2$

$h(x)=x^2-4$

It's required to find $(f\circ h)(2)$

As defined above:

$(f\circ h)(x)=f(h(x))$

Thus:

$(f\circ h)(2)=f(h(2))$

Find h(2):

$h(2)=2^2-4=0$

h(2)=0

Now:

$(f\circ h)(2)=2(0)^2-9(0)+2$

$(f\circ h)(2)=2$

8 0

2 years ago