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arsen [322]
3 years ago
15

Plzzz help. Giving everything.

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0
260° is the correct answer
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Please help will give brainliest please
lyudmila [28]

Answer:

20

Step-by-step explanation:

10 is equal to the side infront of it. 10 +10 = 20

rounding it to the nearest degree will also be 20

8 0
3 years ago
Can someone help me on this math problem ?
faltersainse [42]

Answer:

4/3

Step-by-step explanation:

Given two points, we can find the slope by using

m = (y2-y1)/(x2-x1)

    = (20 - -16)/(7 - -20)

    = (20+16)/(7+20)

    = 36/27

   =4/3

8 0
3 years ago
Helppppppppppppppppppppppppp
Reptile [31]

Answer:

-4/3

Step-by-step explanation:

the formula for slope of a line is Y2-Y1

X2-X1

taking any two points from the table ,

(-1-3)÷(2-(-1))

-4/3

3 0
2 years ago
Read 2 more answers
Compute 33(0.5) - 6(0.5) - 7/2.
lora16 [44]
Hi there! The answer is 10.

33(0.5) - 6(0.5) -  \frac{7}{2}
We can use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Since we cannot work inside the parenthesis in this question and since we don't have exponents, we can move on to multiplying.
16.5 - 3 -  \frac{7}{2}

Our next step would be subtracting. To make the process of subtracting some easier, I'll first change the fraction into a decimal.
16.5 - 3 - 3.5

Finally subtract.
13.5 - 3.5 = 10

The answer is 10.
~ Hope this helps you!
5 0
2 years ago
Read 2 more answers
Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

we have

\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

so the line integral is

\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4

6 0
3 years ago
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