Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
The given expression for the area, 81x² - 4y², is a difference of two squares. The first term is the square of 9x and the second term is the square of 2y. The factors of this difference and the therefore the dimensions of the rectangle are, 9x - 2y and 9x + 2y.
6:13 =83
6+13=19
1 part=83÷19
=4.37
6×4.4=26.4
13×4.4=57.2
26.4:57.2
p.s I got how much money only...
sorry
Answer:
-9
Step-by-step explanation:
