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Alina [70]
3 years ago
10

The width of rectangular solid is 20ft, which is 4/5 of its length. The height of it is 2/9 of the sum of the length and width.

What is the volume of the rectangular solid?
V = ? ft to the third power
Mathematics
1 answer:
lilavasa [31]3 years ago
6 0
Let L and H represent length and height, respectively.
.. 20 ft = (4/5)*L
.. L = (5/4)*(20 ft) = 25 ft . . . . . . . . multiply by the reciprocal of the coefficient of L

.. H = (2/9)*(L +20 ft)
.. = (2/9)*(25 ft +20 ft))
.. = (2/9)*(45 ft) = 10 ft

The volume is the product of length, width, and height.
.. V = (25 ft)*(20 ft)*(10 ft) = 5000 ft^3
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Repeat two more times.  That will give you 24 equal peices.

4 0
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An object is launched with a velocity at 64 feet per second from a platform 30 feet high. the function H(t)= -16t2+64t+30 repres
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To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.

H'(t) = -32t + 64

Now find the critical numbers:

-32t + 64 = 0

-32t = -64

t = 2 seconds

Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):

H'(1) = 32

H'(3) = -32

As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.

To find the height, plug t=2 into H(t):

H(2) = -16(2)^2 +64(2) + 30 = 94

The answer is 94 ft at 2 sec.
4 0
3 years ago
The population of a town in 2007 is 113, 505
ELEN [110]

from 2007 to 2012 is only 5 years, so we can see this as a compound interest with a rate of 1.2% per annum for 5 years, so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$113505\\ r=rate\to 1.2\%\to \frac{1.2}{100}\dotfill &0.012\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=113505\left(1+\frac{0.012}{1}\right)^{1\cdot 5}\implies A=113505(1.012)^5\implies A\approx 120481

7 0
1 year ago
Find the area of the carpet tile. Then find the area covered by 120 carpet tiles.
weqwewe [10]

The area of the carpet is the amount of space it occupies

  • The area of the carpet tile is 256 square inches
  • The area covered by 120 tiles is 30720 squares inches

<h3>How to determine the carpet area</h3>

The dimension of the carpet tile is 16 inches by 16 inches

So, the area is:

Area = 16 * 16

Evaluate the product

Area = 256

Hence, the area of the carpet tile is 256 square inches

For 120 carpet tiles, the area is:

Area = 120 * 256

Area = 30720

Hence, the area covered by 120 tiles is 30720 squares inches

Read more about areas at:

brainly.com/question/24487155

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Find the coordinates of the points of intersection of the graphs with coordinate axes:
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