Answer:
range of f(x) = [-4, -2) ∪ [2, 8)
a+b+c+d = -4
Step-by-step explanation:
The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.
The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.
The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.
Answer:

this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).

- we know that



this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

using the equation of line:

we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e


this is the equation of the tangent at point (-1,1/e)
F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a
f(x) = (5x+1) / x g(x) = x / (5x+1)
f(1) = 6, but g(6) = 6/31 ≠ 1
So, f(x) and g(x) are NOT inverse functions.
Answer:
x = -37.5
Step-by-step explanation:
Set up a proportion so -5/12.5 = 15/x
Solve for x so -5x = 15(12.5) so -5x = 187.5 so x = -37.5
Answer:
1. first one
2. there are no solutions that i see
Step-by-step explanation: