Answer:
in the ordered pair; ( x = 27/4 , y = 1/4 )
Step-by-step explanation:
Given that:
The system of the equation shown below is:
-2x - 14y = 10
2x + 2y = 14
We are to use the elimination method to determine the ordered pair.
From the above equation:
-2x - 14y = 10 --- (1)
2x + 2y = 14 --- (2)
Add both equation 1 and 2 together in order to eliminate x, then we can solve for y first.
-2x - 14y = 10
<u> 2x + 2y = 14 </u>
<u> 0 - 16y = -4 </u>
<u />
- 16 y = - 4
divide both sides by - 16, Then:
-16y /-16 = -4/-16
y = 1/4
Since y = 1/4, Then from equation (2), x will be :
2x + 2y = 14
2x + 2(1/4) = 14
2x + 1/2 = 14
2x = 14 - 1/2
2x = 13.5
x = 13.5/2
x = 27/4
Thus, in the ordered pair; ( x = 27/4 , y = 1/4 )
Answer:
x=1, y=-6. (1, -6).
Step-by-step explanation:
y=-6x
-2x-7y=40
------------------
-2x-7(-6x)=40
-2x+42x=40
40x=40
x=40/40
x=1
y=-6(1)=-6
SA = LH + LW + WH + 2(1/2LH)
SA = 4*2 + 5*2 + 3*2 + 2*1/2*4*3
SA = 8 + 10 + 6 + 12
SA = 36
Answer:
a
Step-by-step explanation:
6.
4x^2 + 4 = 0
Divide both sides by 4
x^2 + 1 = 0
Use the quadratic formula since this cannot be factored.
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = +- sqrt(-4(1)(1))/2
x = +- sqrt(-4)/2
x = +- 2i/2
x = +- i
x = i or x = -i
Quicker solution:
If you have x^2 = number, then
x = +- sqrt(number)
Once you get to
x^2 + 1 = 0
Subtract 1 from both sides
x^2 = -1
Apply the quick method
x = +- sqrt(-1)
x = +- i
8.
2x^2 + 50 = 0
Divide both sides by 2
x^2 + 25 = 0
Subtract 25 from both sides
x^2 = -25
Apply quick method
x = +- sqrt(25)
x = +- 5i
x = 5i or x = -5i
