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3 years ago

13

A ladder is 10 feet long and rests on a wall. The base of the ladder is 5 feet from the wall. Determine how high the ladder touc

hes the wall.

2 answers:

mr Goodwill [35]3 years ago

8 0

Answer:

8.66

Step-by-step explanation:

Alex Ar [27]3 years ago

5 0

8.660 ft a squared + b squared = c squared

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Will someone please help me?? Need help!

choli [55]

ok I will help u tomorrow I am busy today

5 0

3 years ago

PLEASE HELPPPPPP!!!!Tim sells two types of pizza. He charges $10 for a cheese pizza and $15 for a pepperoni pizza. Yesterday he

mr Goodwill [35]

Answer:

$880

Step-by-step explanation:

48 pepperoni pizza=48*15=720

16 cheese pizza=16*10=160

total=$880

8 0

2 years ago

Read 2 more answers

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

<u>Given equation</u>:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

1 year ago

I dont understand B and C in this question so there are a deck of cards 1-10 i already got A right but B and C i dont understand

r-ruslan [8.4K]

Answer:

see below

Step-by-step explanation:

1 2 3 4 5 6 7 8 9 10 = 10 cards

9 of them have 1 digit on them ( 10 has 2 digits)

P( 1 digit) = number with 1 digit) / total = 9/10

P( not have 1 digit)= number not with 1 digit) / total = 1/10

7 0

3 years ago

Calculator<br> What is the value of x?<br> Enter your answer in the box.<br> X =

iVinArrow [24]

Answer:

x=5

Step-by-step explanation:

According to the Pythogoras Theorem,

(hyp)^2 = (opp)^2 + (adj)^2

(13)^2 = (12)^2 + (x)^2

169 = 144 + (x)^2

(x)^2 = 25

x = 5

3 0

3 years ago

Read 2 more answers