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3 years ago

2x+2y= 24 x=3y What is the value of x+y? I WILL MARK BRAINLIEST AND GIVE 20 POINTS.

1 answer:

3 0

Since this is a system of equations, substitute the value of x into the other equation.

2(3y)+2y=24
6y+2y=24
8y=24
y=3

x=3(3)
x=9

To check my work, substitute my x and y values:
2(9)+2(3)=24
18+6=24
24=24

Your answer is (3,9)

Hope this helps! Have a wonderful day :)

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Let “a” represent Andrew’s age TODAY. Write an expression to represent the situation. Andrew’s age in 4 years.

serious [3.7K]

Answer: 4a

Explanation If ‘a’ represents his age today, and you have to find his age in four years you take 4 multiplied a. (4 x a) putting it together and you would get 4a

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4 years ago

Please help! I'll give out the brainiest!

Oxana [17]

-5n-10>/20
Add 10
-5n>/30
On both sides, divide by 5 on (the coefficient of x)
-n>/6
Therefore n>/-6, so D is correct

8 0

3 years ago

Read 2 more answers

A standard number cube,numbered 1 through 6 on each slide,is rolled 4 times.What is the probability of rolling a 2 on all three

LUCKY_DIMON [66]

Answer:

The answer is 1/216

Step-by-step explanation:

for the first roll, you have a 1/6 chance to roll a 2

same for the other two rolls

so,

1/6*1/6*1/6=1/216

hope that helps

4 0

3 years ago

Find factors of x³+12x²-19x= -20

AleksAgata [21]

Answer:

No Factors

Step-by-step explanation:

$x^3-12x^2-19x+20 = 0\\Let \ p(x) = x^3-12x^2-19x+20$

Factors of 20 = ±1, ±2 , ±4 , ±5 , ±10 and ±20

±1, ±2 and ±3 are not the factors of given polynomial.

Putting x = 4 in the given polynomial

$p(4) = (4)^3+12(4)^2-19(4)+20\\p(4) = 64+192-76+20\\p(4) = 200$

So, x = 4 is not a factor of p(x)

Putting x = -4 in the given equation

$p(-4) = (-4)^3+12(-4)^2-19(4)+20\\p(-4) = -64+192-76+20\\p(-4) = 73$

So, x = -4 in the given equation

Putting x = 5 in the given equation

$p(5) = (5)^3+12(5)^2-19(5)+20\\p(5) = 125+300-95+20\\p(5) = 350$

So, x = 5 is not a factor of p(x)

Putting x = -5 in the given equation

$p(-5) = (-5)^3+12(-5)^2-19(-5)+20\\p(-5) = -125+300+95+20\\p(-5) = 290$

So, x = -5 is not a factor of p(x)

Putting x = 10 in the given equation

$p(10) = (10)^3+12(10)^2-19(10)+20\\p(10) = 1000+1200-190+20\\p(10) = 2030$

So, x = 10 is not a factor of p(x)

Putting x = -10 in the given equation

$p(-10) = (-10)^3+12(-10)^2-19(-10)+20\\p(-10) = -1000+1200+190+20\\p(-10) = 410$

So, x = -10 is not a factor of p(x)

Putting x = 20 in the given equation

$p(20) = (20)^3+12(20)^2-19(20)+20\\p(20) = 8000+4800-380+20\\p(20) = 12440$

So, x = 20 is not a factor of p(x)

Putting x = -20 in the given equation

$p(-20) = (-20)^3+12(-20)^2-19(-20)+20\\p(-20) = -8000+4800+380+20\\p(-20) = -2800$

So, x = -20 is not a factor of p(x)

From the above solution, we conclude that the given equation can not be factorized and thus, has no factors.

6 0

4 years ago

Read 2 more answers

The equation x^2−8x−5=0 can be transformed into the equation (x−p)^2=q, where p and q are real numbers. What is the value of q?

Setler79 [48]

Answer:

x = 5

x = 3

Step-by-step explanation:

The first term is, x2 its coefficient is 1 .

The middle term is, -8x its coefficient is -8 .

The last term, "the constant", is +15

Step-1 : Multiply the coefficient of the first term by the constant 1 • 15 = 15

Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is -8 .

-15 + -1 = -16

-5 + -3 = -8

3 0

2 years ago