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o-na [289]
2 years ago
12

Help plzzzzzzzzzz will mark brainilest

Mathematics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:

Group B has the higher median by 0.5 inches. The IQR for Group A is smaller. IQR for Group B is 2 inches.

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What is 3 3/5 ÷ 1 4/5 =
Marysya12 [62]

Answer:

2

Step-by-step explanation:

3 3/5 : 1 4/5= 2/1 = 2

8 0
3 years ago
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Which graph best represents the feasibility region for the system shown above? ( pics are in this)
zalisa [80]

Consider the system of inequalities

\left\{ \begin{array}{l}  y\ge 2 \\  x\le 6 \\  y\le 3x+2 \\  y\le -x+10. \end{array}\right.

1. Plot all lines that are determined by equalities (see attached diagram)

\left\{ \begin{array}{l}  y=2 \text{ (red line)} \\  x= 6  \text{ (blue line)}\\  y=3x+2 \text{ (green line)} \\  y= -x+10  \text{ (orange line)}. \end{array}\right.

2. Determine which bounded part of the plane you should select:

  1. y\ge 2 means that you should take points with y-coordinates greater than or equal to 2 (top part of the coordinate plane that was formed by the red line);
  2. x\le 6 means that you should take points with x-coordinates less than or equal to 6 (left part of the coordinate plane that was formed by the blue line);
  3. for y\le 3x+2 you can check where the origin is placed. Since 0\le 3\cdot 0+2, the origin belongs to the needed part and you have to take the right part of the coordinate plane that was formed by green line.
  4. for y\le -x+10 you can check where the origin is placed. Since 0\le -1\cdot 0+10, the origin belongs to the needed part and you have to take the bottom part of the coordinate plane that was formed by orange line.

3. According to the previous explanations, the shaded region is as in A diagram.

Answer: correct choice is A.


5 0
3 years ago
Read 2 more answers
What is the missing fraction for 1/6 1/8 1/4 ?/? = 1whole
denis23 [38]
The answer is 11/24.

5 0
3 years ago
484,343 rounded to the nearest thousand
Semmy [17]

Answer:

484,000

Step-by-step explanation:

The hundreds place is less than 5 so you round down.

3 0
3 years ago
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If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
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