Answer:
(a³ - 6b)
Step-by-step explanation:
=
=
(a³ - 6b)
Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.
For two lines y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate k1 and k2.
To calculate the slope k of any line, you have to change the equation to y=kx+b
For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))
For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)
Now you can get the answer: The two lines neither parallel nor perpendicular.
Answer:
0.35355339059
Step-by-step explanation:
23 / 50 = 0.46
0.46 converted to a percent is 46%
Check the picture below.
so let's use those two points the line passes through to get its slope.
![\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-12-0}{4-2}\implies \cfrac{-12}{2}\implies -6](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-12%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B-12-0%7D%7B4-2%7D%5Cimplies%20%5Ccfrac%7B-12%7D%7B2%7D%5Cimplies%20-6)