Let P = percent of discount
(290-188)/290 = P/100
102/290 = P/100
290P = (102)(100)
290P = 10,200
Solve for P to find your answer.
Answer:
32 and 39
Step-by-step explanation:
The common difference d for the sequence is 7
1st term of the sequence a1 is 11.
4th (a4) and 5th (a5) term of the sequence are required
nth term of an arithmetic sequence an =a1+(n-1)d
a4=11+(4-1)7=32
a5=11+(5-1)7=39
Answer:
Interpreting as: X=a-sqrt b X=a+sqrt b
Input:
X = a - sqrt(b) X = a + sqrt(b)
Alternate forms:
{a = (sqrt(b) + 1) X, a = X - sqrt(b), b = 0 ∨ X = -1}
{a = (sqrt(b) + 1) X, a + sqrt(b) = X, sqrt(b) (X + 1) = 0}
Answer:
Time machine one = 3.56
Time machine two = 4.56
Step-by-step explanation:
Let machine 2 do the job in x hours
Let machine 1 do the job in x - 1 hours.
The general formula for this problem is
Time = A*B/(A + B)
Givens
Time = 2 hours
B = x hours alone
A = x - 1 hours alone.
#################
x *( x - 1)
======= = 2
(x + x - 1)
(x^2 - x)/(2x - 1) = 2
x^2 - x = 2(2x - 1)
x^2 - x = 4x - 2
x^2 - 5x + 2 = 0
a = 1
b = - 5
c = 2
This gives 2 roots
x = 4.56
x = 0.43
The second root will not work because when 1 is subtracted from 0.43 the time give will be minus, which won't work.
Time for machine 2 is 4.56
The time for machine 1 is 3.56
Check
(A * B)/(A + B) = 2
A = 4.56
B = 3.56
Time = 4.56*3.56/(4.56 + 3.56)
Time = 16.2336/(8.12)
Time = 1.9992
The rounding error in the check comes from the rounding error in the times.
