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3 years ago

5

Abbas is two years younger than Brad. Two years ago, the sum of their ages was the same as Brad's current age. How old are the b

oys now?

1 answer:

Klio2033 [76]3 years ago

6 0

Answer:

I believe they are younger

Step-by-step explanation:

I hope this helps

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The Jayden family eats at a restaurant that is having a 15% discount promotion. Their meal costs $78.72 before the discount, and

Scorpion4ik [409]

If I’m not mistaking it is either 80.29 or 80.30 after rounding,I’m not sure.

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3 years ago

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Change 5 out of 19 to a percentage give tour answer to 1 decimal place

almond37 [142]

26.3 (5 out of 19) and 58.5 (72 out of 123)
May be wrong, but pretty sure it’s right

4 0

3 years ago

Which property states that if a = b and b = c, then a = c?

Step2247 [10]

Transitive.

Associative is (a + b) + c = a + (b + c)

Commutative is a + b = b + a

Reflexive is a = a

Thus, transitive is the correct answer.

Hope this helps!

6 0

3 years ago

The number under the radical sign or square root sign is called the

GrogVix [38]

Answer:

Radicand

Step-by-step explanation:

The term (or number) whose square root is being considered is known as the radicand. The radicand is the number or expression underneath the radical sign, in this case 9.

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3 years ago

In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38

Ganezh [65]

Answer:

a

$0.716 < p < 0.744$

b

$0.3498 < p < 0.4089$

c

With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at b

Step-by-step explanation:

From the question we are told that

The sample size is $n = 1003$

The number that complained about dirty or ill-equipped bathrooms is $e = 732$

The number that complained about loud or distracting diners at other tables is $q = 381$

Given that the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100- 95)\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Considering question a

The sample proportion is mathematically represented as

$\r p = \frac{e}{n}$

=> $\r p = \frac{732}{1003}$

=> $\r p = 0.73$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p (1- \r p)}{n} }$

$E = 1.96* \sqrt{ \frac{ 0.73 (1- 0.73)}{1003} }$

$E = 0.01402$

The 95% confidence interval is

$\r p - E < p < \r p +E$

$0.73 - 0.01402 < p < 0.73 + 0.01402$

$0.716 < p < 0.744$

Considering question b

The sample proportion is mathematically represented as

$\r p = \frac{q}{n}$

=> $\r p = \frac{381}{1003}$

=> $\r p = 0.3799$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p (1- \r p)}{n} }$

$E = 1.96* \sqrt{ \frac{ 0.3799 (1- 0.3799)}{1003} }$

$E = 0.0300$

The 95% confidence interval is

$\r p - E < p < \r p +E$

$0.3798 - 0.0300 < p < 0.3798 + 0.0300$

$0.3498 < p < 0.4089$

8 0

3 years ago