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3 years ago

Find the volume and total surface area of a cone with a radius of 3 and a height of 5.

Mathematics

1 answer:

azamat3 years ago

5 0

Answer:

<h2>hope it helps you see the attachment for further information ✌✌✌✌✌✌✌</h2>

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I’m confused on this one

tatyana61 [14]

$6\sqrt2$

Why?

We have the isosceles right triangle. The length of legs are 6. Use the Pythagorean theorem:

$h^2=6^2+6^2\\\\h^2=36+36\\\\h^2=36\cdot2\to h=\sqrt{36\cdot2}\\\\h=\sqrt{36}\cdot\sqrt2\\\\h=6\sqrt2$

In general, the formula for calculating the hypotenuse in an isosceles right triangle is $h=a\sqrt2$

a - a leg, h - a hypotenuse

7 0

3 years ago

two angles are supplementary if the sum of their measures is 180 degrees. if one angles measure is 90 degrees more than twice th

inessss [21]

The measures of the other angles is 45°
90+2x=180
2x=90
x=45

3 0

3 years ago

The infinite sequence $T=\{t_0,t_1,t_2,\ldots\}$ is defined as $t_0=0,$ $t_1=1,$ and $t_n=t_{n-2}+t_{n-1}$ for all integers $n&g

katrin [286]

$t_n$ are the Fibonacci numbers,

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, ...

Taken modulo 7, we get the sequence

0, 1, 1, 2, 3, 5, 1, 6, 0, 6, 6, 5, 4, 2, 6, 1, ...

that repeats with period 16 (this is known as the 7th Pisano period).

This is to say,

$t_a\equiv t_{16n+5}\equiv t_5\equiv5\pmod7$

$t_b\equiv t_{16n+10}\equiv t_{10}\equiv6\pmod7$

$t_c\equiv t_{16n+15}\equiv t_{15}\equiv1\pmod7$

so that

$(t_a+t_b+t_c)\equiv(5+6+1)\equiv\boxed5\pmod7$

6 0

3 years ago

All 8th grade students at Franklin Middle School

rusak2 [61]

Answer:

B. 125

Step-by-step explanation:

72 did not return the permission slips.

125-72= 53

So therefore 53 students are going on the field trip.

5 0

4 years ago

A moving trailer with a speed of 70km/h slows down its speed by 15% within 30 seconds. calculate the declaration of the trailer.

antoniya [11.8K]

Answer:

declaration = - 0.55 m/s²

Step-by-step explanation:

The declaration is a negative accelaration.

Therefore:

$a = \frac{v-u}{t}$

a = ?

v = 70 of 15% = 10.5 km/h to m/s = 2.9 m/s

u = 70 km/h to m/s = 19.4 m/s

t = 30 seconds

$a = \frac{2.9-19.4}{30}\\$

a = - 0.55 m/s²

7 0

3 years ago