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2 years ago

What is software?

Computers and Technology

1 answer:

vivado [14]2 years ago

5 0

Answer:

Anything that tells hardware what to do and how to do it.

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A group of 8 bits is called a... A. hunch B. byte C. dozen D. snack

Mama L [17]

I think that it's called a byte.

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3 years ago

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What is the interface in Java programming Language? Why do we need to use it?

Alenkasestr [34]

To accustom to several different language-speaking countries. One program is often used internationally so having a language setup is very important.

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3 years ago

A network technician is setting up a wireless access point in the front office of a small company. The technician needs to disab

VladimirAG [237]

Answer:

He should disable UPnP technology to disallow devices to dynamically add themselves to the network without configuration.

Explanation:

UPnP stands for Universal Plug n Play.
It is an easiest way that allows gadgets to find all other devices connecting to your network.
This can also modify router settings to allow devices from outside the network to access the router.
External IP address can also be obtained by the gadget and a new port forwarding map can be set
So from all perspectives, UPnP is an open invitation for hackers to scan for the ports and hack into the device.
UPnP is a vulnerability to the secure system

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3 years ago

Write a complete Java program called Rooter that gets a positive integer called "start" from the user at the command line and th

Nataly_w [17]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Rooter{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int start;

System.out.print("Start: ");

start = input.nextInt();

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

while(start>=0){

System.out.println(Math.sqrt(start));

start--; }

}

Explanation:

This declares start as integer

int start;

This prompts the user for input

System.out.print("Start: ");

This gets input for start

start = input.nextInt();

The following is repeated until the user input is valid i.e. positive

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

The following while loop prints the square root of each number till 0

while(start>=0){

System.out.println(Math.sqrt(start));

start--; }

4 0

2 years ago

Write a program that uses an STL List of integers. a. The program will insert two integers, 5 and 6, at the end of the list. Nex

poizon [28]

Answer:

answer:

#include <iostream>

#include<list>

using namespace std;

bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;

l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";

/*Display the list*/

cout<<endl; return 0;

}

5 0

3 years ago

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