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STALIN [3.7K]
3 years ago
14

Which graph represents the line 10x + 5y = 20?

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0
The graph of <span>10x + 5y = 20 is attached.

</span>
<span>A line graphed on a Coordinate plane with x axis ranging from negative 4 to 6 and y axis ranging from negative 3 to 7. The line passes through the points begin ordered pair 1 comma 2 end ordered pair and begin ordered pair 3 comma negative 2 end ordered pair.</span>

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sasho [114]

Answer:

number 1. is C and number 2. is A

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3 years ago
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Identify the constants in the expression: 7-5x+1?For 6th grade.
erik [133]

Answer:

The constants are 7 and 1

Step-by-step explanation:

7 0
3 years ago
Ciny bought s car for 21, 33. A few years later, she sd the car for 19, 700. Find the percent of change in the value
Lina20 [59]
823.582% increase between the initial price and the current price.
8 0
3 years ago
O is the centroid. Find the value of x. (Sorry if u cant see the photo :/, but this is Geometry btw)
klemol [59]

Answer: x = 6

==============================================

Explanation:

The medians of a triangle meet up at the centroid in such a way that they cut each other at a ratio of 2:1, meaning that one part of the median is twice as long as the other. In this case, MO is two times longer than OP, so,

OP = 2*MO

and

MP = MO + OP

MP = MO + 2*MO .... replace OP with 2*MO

MP = 3*MO

9x-24 = 3*(x+4) ... plug in the given expressions

9x-24 = 3x+12

9x-3x = 12+24

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x = 36/6

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8 0
3 years ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
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