A sum of 16 and a difference of 2
2 answers:
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Answer:
Let the complaints by Industry be CbI
CbI Frequency
Bank 26
Cable 44
Car 42
Cell 60
Collection 28
b) Percentages
CbI percentage (%)
Bank 13
Cable 22
Car 21
Cell 30
Collection 14
c) The industry with the highest number of complaints is the Cell Industry.
d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.
Step-by-step explanation:
a) The frequencies are simply the number of times each industry sector sent in a complaint. So, it's straight forward to present.
b) The percentage for each industry is done in comparison to the the total amount of complaints received.
Percentage for each industry = 100% × (Number of complaints from that industry)/(Total number of complaints)
Total amount of complaints received = 200
For Bank industry,
Percentage = 100% × (26/200) = 13%
For the Cable Industry,
Percentage = 100% × (44/200) = 22%
For Car industry,
Percentage = 100% × (42/200) = 21%
For Cell industry,
Percentage = 100% × (60/200) = 30%
For Collection industry,
Percentage = 100% × (28/200) = 14%
c) The industry with the highest number of complaints is the one with the highest frequency and percentage, and that is the Cell Industry.
d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C
<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)
Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C
